Base | Representation |
---|---|
bin | 110111100110000110110101… |
… | …110010100001001100000001 |
3 | 1012001202001020221100210221012 |
4 | 313212012311302201030001 |
5 | 224022033011214110332 |
6 | 2224010525302010305 |
7 | 102334232354216633 |
oct | 6746066562411401 |
9 | 1161661227323835 |
10 | 244511243113217 |
11 | 709aa6aa384893 |
12 | 2350bb00716995 |
13 | a658407b98342 |
14 | 445459b938a53 |
15 | 1d4047295c3b2 |
hex | de61b5ca1301 |
244511243113217 has 2 divisors, whose sum is σ = 244511243113218. Its totient is φ = 244511243113216.
The previous prime is 244511243113169. The next prime is 244511243113373. The reversal of 244511243113217 is 712311342115442.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 209046371566096 + 35464871547121 = 14458436^2 + 5955239^2 .
It is a cyclic number.
It is not a de Polignac number, because 244511243113217 - 210 = 244511243112193 is a prime.
It is not a weakly prime, because it can be changed into another prime (244511243133217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122255621556608 + 122255621556609.
It is an arithmetic number, because the mean of its divisors is an integer number (122255621556609).
Almost surely, 2244511243113217 is an apocalyptic number.
It is an amenable number.
244511243113217 is a deficient number, since it is larger than the sum of its proper divisors (1).
244511243113217 is an equidigital number, since it uses as much as digits as its factorization.
244511243113217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 161280, while the sum is 41.
Adding to 244511243113217 its reverse (712311342115442), we get a palindrome (956822585228659).
The spelling of 244511243113217 in words is "two hundred forty-four trillion, five hundred eleven billion, two hundred forty-three million, one hundred thirteen thousand, two hundred seventeen".
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