245112131230033 has 4 divisors (see below), whose sum is σ = 245399484256948. Its totient is φ = 244824778203120.

The previous prime is 245112131229949. The next prime is 245112131230039. The reversal of 245112131230033 is 330032131211542.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 86462790340369 + 158649340889664 = 9298537^2 + 12595608^2 .

It is a cyclic number.

It is not a de Polignac number, because 245112131230033 - 2⁹ = 245112131229521 is a prime.

It is a super-2 number, since 2×245112131230033² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 245112131229977 and 245112131230004.

It is not an unprimeable number, because it can be changed into a prime (245112131230039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143676512178 + ... + 143676513883.

It is an arithmetic number, because the mean of its divisors is an integer number (61349871064237).

Almost surely, 2^{245112131230033} is an apocalyptic number.

It is an amenable number.

245112131230033 is a deficient number, since it is larger than the sum of its proper divisors (287353026915).

245112131230033 is an equidigital number, since it uses as much as digits as its factorization.

245112131230033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 287353026914.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 245112131230033 its reverse (330032131211542), we get a palindrome (575144262441575).

The spelling of 245112131230033 in words is "two hundred forty-five trillion, one hundred twelve billion, one hundred thirty-one million, two hundred thirty thousand, thirty-three".