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245153433001 = 1991231926799
BaseRepresentation
bin1110010001010001001…
…0001000010110101001
3212102210011102202001211
43210110102020112221
513004033234324001
6304342200513121
723466062540551
oct3442422102651
9772704382054
10245153433001
1194a727a3784
123b61947b7a1
131a16bc61979
14bc18c90161
15659c5be351
hex39144885a9

245153433001 has 4 divisors (see below), whose sum is σ = 246385360000. Its totient is φ = 243921506004.

The previous prime is 245153432969. The next prime is 245153433011. The reversal of 245153433001 is 100334351542.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 245153433001 - 25 = 245153432969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (245153433011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615963201 + ... + 615963598.

It is an arithmetic number, because the mean of its divisors is an integer number (61596340000).

Almost surely, 2245153433001 is an apocalyptic number.

It is an amenable number.

245153433001 is a deficient number, since it is larger than the sum of its proper divisors (1231926999).

245153433001 is a wasteful number, since it uses less digits than its factorization.

245153433001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1231926998.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 245153433001 its reverse (100334351542), we get a palindrome (345487784543).

The spelling of 245153433001 in words is "two hundred forty-five billion, one hundred fifty-three million, four hundred thirty-three thousand, one".

Divisors: 1 199 1231926799 245153433001