Base | Representation |
---|---|
bin | 1110010001010001010… |
… | …0010100000001111001 |
3 | 212102210012111210212011 |
4 | 3210110110110001321 |
5 | 13004033411130423 |
6 | 304342221045521 |
7 | 23466100442533 |
oct | 3442424240171 |
9 | 772705453764 |
10 | 245154005113 |
11 | 94a730545a6 |
12 | 3b6196b68a1 |
13 | 1a16c1021b4 |
14 | bc18d9c853 |
15 | 659c683b0d |
hex | 3914514079 |
245154005113 has 4 divisors (see below), whose sum is σ = 245186573940. Its totient is φ = 245121436288.
The previous prime is 245154005099. The next prime is 245154005123. The reversal of 245154005113 is 311500451542.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 143681176809 + 101472828304 = 379053^2 + 318548^2 .
It is a cyclic number.
It is not a de Polignac number, because 245154005113 - 233 = 236564070521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (245154005123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16273120 + ... + 16288177.
It is an arithmetic number, because the mean of its divisors is an integer number (61296643485).
Almost surely, 2245154005113 is an apocalyptic number.
It is an amenable number.
245154005113 is a deficient number, since it is larger than the sum of its proper divisors (32568827).
245154005113 is an equidigital number, since it uses as much as digits as its factorization.
245154005113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32568826.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 245154005113 its reverse (311500451542), we get a palindrome (556654456655).
The spelling of 245154005113 in words is "two hundred forty-five billion, one hundred fifty-four million, five thousand, one hundred thirteen".
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