Base | Representation |
---|---|
bin | 1110010001100011011… |
… | …0011010111011011011 |
3 | 212102222111121112212111 |
4 | 3210120312122323123 |
5 | 13004212343231011 |
6 | 304353535053151 |
7 | 23501013034645 |
oct | 3443066327333 |
9 | 772874545774 |
10 | 245230055131 |
11 | 95001a78056 |
12 | 3b63b0711b7 |
13 | 1a181aab6c9 |
14 | bc25117895 |
15 | 65a41a7121 |
hex | 3918d9aedb |
245230055131 has 4 divisors (see below), whose sum is σ = 246282544872. Its totient is φ = 244177565392.
The previous prime is 245230055129. The next prime is 245230055141. The reversal of 245230055131 is 131550032542.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 245230055131 - 21 = 245230055129 is a prime.
It is a super-2 number, since 2×2452300551312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 245230055093 and 245230055102.
It is not an unprimeable number, because it can be changed into a prime (245230055101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 526244521 + ... + 526244986.
It is an arithmetic number, because the mean of its divisors is an integer number (61570636218).
Almost surely, 2245230055131 is an apocalyptic number.
245230055131 is a deficient number, since it is larger than the sum of its proper divisors (1052489741).
245230055131 is a wasteful number, since it uses less digits than its factorization.
245230055131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1052489740.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 245230055131 its reverse (131550032542), we get a palindrome (376780087673).
The spelling of 245230055131 in words is "two hundred forty-five billion, two hundred thirty million, fifty-five thousand, one hundred thirty-one".
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