Base | Representation |
---|---|
bin | 110111110000111010100110… |
… | …011101111110101111111001 |
3 | 1012011101001111000111011212021 |
4 | 313300322212131332233321 |
5 | 224121220210421210431 |
6 | 2225340050030114441 |
7 | 102442006063463422 |
oct | 6760724635765771 |
9 | 1164331430434767 |
10 | 245254015413241 |
11 | 71166709a3a56a |
12 | 2360ba5564ba21 |
13 | a6b047b866943 |
14 | 447c5016a0649 |
15 | 1d54946ab3b11 |
hex | df0ea677ebf9 |
245254015413241 has 2 divisors, whose sum is σ = 245254015413242. Its totient is φ = 245254015413240.
The previous prime is 245254015413079. The next prime is 245254015413299. The reversal of 245254015413241 is 142314510452542.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 200488013665641 + 44766001747600 = 14159379^2 + 6690740^2 .
It is a cyclic number.
It is not a de Polignac number, because 245254015413241 - 211 = 245254015411193 is a prime.
It is not a weakly prime, because it can be changed into another prime (245254015411241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122627007706620 + 122627007706621.
It is an arithmetic number, because the mean of its divisors is an integer number (122627007706621).
Almost surely, 2245254015413241 is an apocalyptic number.
It is an amenable number.
245254015413241 is a deficient number, since it is larger than the sum of its proper divisors (1).
245254015413241 is an equidigital number, since it uses as much as digits as its factorization.
245254015413241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768000, while the sum is 43.
Adding to 245254015413241 its reverse (142314510452542), we get a palindrome (387568525865783).
The spelling of 245254015413241 in words is "two hundred forty-five trillion, two hundred fifty-four billion, fifteen million, four hundred thirteen thousand, two hundred forty-one".
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