Base | Representation |
---|---|
bin | 110111110010001101110001… |
… | …011100101110010011100001 |
3 | 1012011200120222211012121220012 |
4 | 313302031301130232103201 |
5 | 224124201104433021023 |
6 | 2225445055413454305 |
7 | 102451320121622366 |
oct | 6762156134562341 |
9 | 1164616884177805 |
10 | 245343320204513 |
11 | 711a0577193a93 |
12 | 23625219641395 |
13 | a6b8a116365bb |
14 | 448297411046d |
15 | 1d56e21db7978 |
hex | df237172e4e1 |
245343320204513 has 4 divisors (see below), whose sum is σ = 245344628840880. Its totient is φ = 245342011568148.
The previous prime is 245343320204471. The next prime is 245343320204539. The reversal of 245343320204513 is 315402023343542.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 245343320204513 - 210 = 245343320203489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (245343325204513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 654036923 + ... + 654411936.
It is an arithmetic number, because the mean of its divisors is an integer number (61336157210220).
Almost surely, 2245343320204513 is an apocalyptic number.
It is an amenable number.
245343320204513 is a deficient number, since it is larger than the sum of its proper divisors (1308636367).
245343320204513 is a wasteful number, since it uses less digits than its factorization.
245343320204513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1308636366.
The product of its (nonzero) digits is 1036800, while the sum is 41.
The spelling of 245343320204513 in words is "two hundred forty-five trillion, three hundred forty-three billion, three hundred twenty million, two hundred four thousand, five hundred thirteen".
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