245400402154113 has 12 divisors (see below), whose sum is σ = 354468184501860. Its totient is φ = 163599835666176.

The previous prime is 245400402154111. The next prime is 245400402154133. The reversal of 245400402154113 is 311451204004542.

245400402154113 is a `hidden beast` number, since 2 + 4 + 5 + 40 + 0 + 40 + 21 + 541 + 13 = 666.

245400402154113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 56667291061824 + 188733111092289 = 7527768^2 + 13738017^2 .

It is not a de Polignac number, because 245400402154113 - 2¹ = 245400402154111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (245400402154111) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 32423256 + ... + 39269177.

It is an arithmetic number, because the mean of its divisors is an integer number (29539015375155).

Almost surely, 2^{245400402154113} is an apocalyptic number.

It is an amenable number.

245400402154113 is a deficient number, since it is larger than the sum of its proper divisors (109067782347747).

245400402154113 is a wasteful number, since it uses less digits than its factorization.

245400402154113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72072768 (or 72072765 counting only the distinct ones).

The product of its (nonzero) digits is 76800, while the sum is 36.

Adding to 245400402154113 its reverse (311451204004542), we get a palindrome (556851606158655).

The spelling of 245400402154113 in words is "two hundred forty-five trillion, four hundred billion, four hundred two million, one hundred fifty-four thousand, one hundred thirteen".