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245421414543433 is a prime number
BaseRepresentation
bin110111110011010110100000…
…001110111111000001001001
31012011222001120100111002100011
4313303112200032333001021
5224131441024110342213
62225545012534311521
7102460053303555652
oct6763264016770111
91164861510432304
10245421414543433
1171220701428757
12236383931b85a1
13a6c31a8a04bbb
144486661b4a529
151d58e92e0b03d
hexdf35a03bf049

245421414543433 has 2 divisors, whose sum is σ = 245421414543434. Its totient is φ = 245421414543432.

The previous prime is 245421414543377. The next prime is 245421414543469. The reversal of 245421414543433 is 334345414124542.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 243398315107984 + 2023099435449 = 15601228^2 + 1422357^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-245421414543433 is a prime.

It is not a weakly prime, because it can be changed into another prime (245421414540433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122710707271716 + 122710707271717.

It is an arithmetic number, because the mean of its divisors is an integer number (122710707271717).

Almost surely, 2245421414543433 is an apocalyptic number.

It is an amenable number.

245421414543433 is a deficient number, since it is larger than the sum of its proper divisors (1).

245421414543433 is an equidigital number, since it uses as much as digits as its factorization.

245421414543433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11059200, while the sum is 49.

Adding to 245421414543433 its reverse (334345414124542), we get a palindrome (579766828667975).

The spelling of 245421414543433 in words is "two hundred forty-five trillion, four hundred twenty-one billion, four hundred fourteen million, five hundred forty-three thousand, four hundred thirty-three".