Base | Representation |
---|---|
bin | 110111110011010110100000… |
… | …001110111111000001001001 |
3 | 1012011222001120100111002100011 |
4 | 313303112200032333001021 |
5 | 224131441024110342213 |
6 | 2225545012534311521 |
7 | 102460053303555652 |
oct | 6763264016770111 |
9 | 1164861510432304 |
10 | 245421414543433 |
11 | 71220701428757 |
12 | 236383931b85a1 |
13 | a6c31a8a04bbb |
14 | 4486661b4a529 |
15 | 1d58e92e0b03d |
hex | df35a03bf049 |
245421414543433 has 2 divisors, whose sum is σ = 245421414543434. Its totient is φ = 245421414543432.
The previous prime is 245421414543377. The next prime is 245421414543469. The reversal of 245421414543433 is 334345414124542.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 243398315107984 + 2023099435449 = 15601228^2 + 1422357^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-245421414543433 is a prime.
It is not a weakly prime, because it can be changed into another prime (245421414540433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122710707271716 + 122710707271717.
It is an arithmetic number, because the mean of its divisors is an integer number (122710707271717).
Almost surely, 2245421414543433 is an apocalyptic number.
It is an amenable number.
245421414543433 is a deficient number, since it is larger than the sum of its proper divisors (1).
245421414543433 is an equidigital number, since it uses as much as digits as its factorization.
245421414543433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11059200, while the sum is 49.
Adding to 245421414543433 its reverse (334345414124542), we get a palindrome (579766828667975).
The spelling of 245421414543433 in words is "two hundred forty-five trillion, four hundred twenty-one billion, four hundred fourteen million, five hundred forty-three thousand, four hundred thirty-three".
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