Base | Representation |
---|---|
bin | 1110011100010010010… |
… | …1100111101010110011 |
3 | 212201102022020120201022 |
4 | 3213010211213222303 |
5 | 13031113000111034 |
6 | 305551502530055 |
7 | 23632300345055 |
oct | 3470445475263 |
9 | 781368216638 |
10 | 248111332019 |
11 | 96250419021 |
12 | 40103b9692b |
13 | 1a5209c5285 |
14 | c019a578d5 |
15 | 66c20e8b2e |
hex | 39c4967ab3 |
248111332019 has 2 divisors, whose sum is σ = 248111332020. Its totient is φ = 248111332018.
The previous prime is 248111332009. The next prime is 248111332039. The reversal of 248111332019 is 910233111842.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 248111332019 - 28 = 248111331763 is a prime.
It is a super-2 number, since 2×2481113320192 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 248111332019.
It is not a weakly prime, because it can be changed into another prime (248111332009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124055666009 + 124055666010.
It is an arithmetic number, because the mean of its divisors is an integer number (124055666010).
Almost surely, 2248111332019 is an apocalyptic number.
248111332019 is a deficient number, since it is larger than the sum of its proper divisors (1).
248111332019 is an equidigital number, since it uses as much as digits as its factorization.
248111332019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 35.
The spelling of 248111332019 in words is "two hundred forty-eight billion, one hundred eleven million, three hundred thirty-two thousand, nineteen".
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