Base | Representation |
---|---|
bin | 1001001111100111… |
… | …0010110010100001 |
3 | 20101221012020020111 |
4 | 2103321302302201 |
5 | 20040214312433 |
6 | 1050121011321 |
7 | 115330363141 |
oct | 22371626241 |
9 | 6357166214 |
10 | 2481400993 |
11 | 1063760325 |
12 | 593023b41 |
13 | 307119916 |
14 | 1977ac921 |
15 | e7ca4dcd |
hex | 93e72ca1 |
2481400993 has 2 divisors, whose sum is σ = 2481400994. Its totient is φ = 2481400992.
The previous prime is 2481400919. The next prime is 2481401029. The reversal of 2481400993 is 3990041842.
2481400993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2481235344 + 165649 = 49812^2 + 407^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2481400993 is a prime.
It is a super-2 number, since 2×24814009932 = 12314701776122772098, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2481400193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1240700496 + 1240700497.
It is an arithmetic number, because the mean of its divisors is an integer number (1240700497).
Almost surely, 22481400993 is an apocalyptic number.
It is an amenable number.
2481400993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2481400993 is an equidigital number, since it uses as much as digits as its factorization.
2481400993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 40.
The square root of 2481400993 is about 49813.6627141591. The cubic root of 2481400993 is about 1353.8347289925.
The spelling of 2481400993 in words is "two billion, four hundred eighty-one million, four hundred thousand, nine hundred ninety-three".
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