Base | Representation |
---|---|
bin | 111000011011101110011101… |
… | …010011101011011001000011 |
3 | 1012112210022001000021212112012 |
4 | 320123232131103223121003 |
5 | 230012420213031042311 |
6 | 2235511343505323135 |
7 | 103164364062530513 |
oct | 7033563523533103 |
9 | 1175708030255465 |
10 | 248195914315331 |
11 | 720a03291a4454 |
12 | 23a060456364ab |
13 | a864a0b177568 |
14 | 4540a63da3843 |
15 | 1da622a64778b |
hex | e1bb9d4eb643 |
248195914315331 has 2 divisors, whose sum is σ = 248195914315332. Its totient is φ = 248195914315330.
The previous prime is 248195914315207. The next prime is 248195914315417. The reversal of 248195914315331 is 133513419591842.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 248195914315331 - 230 = 248194840573507 is a prime.
It is a super-2 number, since 2×2481959143153312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (248195914315631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124097957157665 + 124097957157666.
It is an arithmetic number, because the mean of its divisors is an integer number (124097957157666).
Almost surely, 2248195914315331 is an apocalyptic number.
248195914315331 is a deficient number, since it is larger than the sum of its proper divisors (1).
248195914315331 is an equidigital number, since it uses as much as digits as its factorization.
248195914315331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13996800, while the sum is 59.
The spelling of 248195914315331 in words is "two hundred forty-eight trillion, one hundred ninety-five billion, nine hundred fourteen million, three hundred fifteen thousand, three hundred thirty-one".
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