Base | Representation |
---|---|
bin | 11101101011110… |
… | …00000110010001 |
3 | 122100112201212102 |
4 | 32311320012101 |
5 | 1002221120213 |
6 | 40413010145 |
7 | 6112334306 |
oct | 1665700621 |
9 | 570481772 |
10 | 249004433 |
11 | 118613797 |
12 | 6b483955 |
13 | 3c784502 |
14 | 250db0ad |
15 | 16cd9158 |
hex | ed78191 |
249004433 has 2 divisors, whose sum is σ = 249004434. Its totient is φ = 249004432.
The previous prime is 249004429. The next prime is 249004489. The reversal of 249004433 is 334400942.
249004433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 246238864 + 2765569 = 15692^2 + 1663^2 .
It is a cyclic number.
It is not a de Polignac number, because 249004433 - 22 = 249004429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 249004396 and 249004405.
It is not a weakly prime, because it can be changed into another prime (249007433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124502216 + 124502217.
It is an arithmetic number, because the mean of its divisors is an integer number (124502217).
Almost surely, 2249004433 is an apocalyptic number.
It is an amenable number.
249004433 is a deficient number, since it is larger than the sum of its proper divisors (1).
249004433 is an equidigital number, since it uses as much as digits as its factorization.
249004433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
The square root of 249004433 is about 15779.8743024145. The cubic root of 249004433 is about 629.1231885827.
The spelling of 249004433 in words is "two hundred forty-nine million, four thousand, four hundred thirty-three".
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