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249051220043 is a prime number
BaseRepresentation
bin1110011111110010011…
…1000000100001001011
3212210211210210211200212
43213330213000201023
513040024103020133
6310225035551335
723664502304303
oct3477447004113
9783753724625
10249051220043
1196692a1488a
12403268bb54b
131a640646532
14c0a87d8603
1567298a4148
hex39fc9c084b

249051220043 has 2 divisors, whose sum is σ = 249051220044. Its totient is φ = 249051220042.

The previous prime is 249051220037. The next prime is 249051220081. The reversal of 249051220043 is 340022150942.

249051220043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 249051220043 - 26 = 249051219979 is a prime.

It is a super-3 number, since 3×2490512200433 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 249051219991 and 249051220009.

It is not a weakly prime, because it can be changed into another prime (249051220543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124525610021 + 124525610022.

It is an arithmetic number, because the mean of its divisors is an integer number (124525610022).

Almost surely, 2249051220043 is an apocalyptic number.

249051220043 is a deficient number, since it is larger than the sum of its proper divisors (1).

249051220043 is an equidigital number, since it uses as much as digits as its factorization.

249051220043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 249051220043 its reverse (340022150942), we get a palindrome (589073370985).

The spelling of 249051220043 in words is "two hundred forty-nine billion, fifty-one million, two hundred twenty thousand, forty-three".