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249148433 is a prime number
BaseRepresentation
bin11101101100110…
…11010000010001
3122100211001101202
432312123100101
51002240222213
640420040545
76113504162
oct1666332021
9570731352
10249148433
111187019a6
126b533155
133c804c11
1425137769
1516d16b58
hexed9b411

249148433 has 2 divisors, whose sum is σ = 249148434. Its totient is φ = 249148432.

The previous prime is 249148423. The next prime is 249148441. The reversal of 249148433 is 334841942.

249148433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 176677264 + 72471169 = 13292^2 + 8513^2 .

It is a cyclic number.

It is not a de Polignac number, because 249148433 - 214 = 249132049 is a prime.

It is a super-3 number, since 3×2491484333 (a number of 26 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (249148423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124574216 + 124574217.

It is an arithmetic number, because the mean of its divisors is an integer number (124574217).

Almost surely, 2249148433 is an apocalyptic number.

It is an amenable number.

249148433 is a deficient number, since it is larger than the sum of its proper divisors (1).

249148433 is an equidigital number, since it uses as much as digits as its factorization.

249148433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 82944, while the sum is 38.

The square root of 249148433 is about 15784.4364169266. The cubic root of 249148433 is about 629.2444398125.

The spelling of 249148433 in words is "two hundred forty-nine million, one hundred forty-eight thousand, four hundred thirty-three".