Base | Representation |
---|---|
bin | 100100010111100011110… |
… | …000011001011010100001 |
3 | 22211220212100021201200201 |
4 | 210113203300121122201 |
5 | 311421323430122032 |
6 | 5152040523345201 |
7 | 345363301651102 |
oct | 44274360313241 |
9 | 8756770251621 |
10 | 2499197114017 |
11 | 8839a368714a |
12 | 344440082201 |
13 | 15189a25b786 |
14 | 88d671d63a9 |
15 | 450233b88e7 |
hex | 245e3c196a1 |
2499197114017 has 2 divisors, whose sum is σ = 2499197114018. Its totient is φ = 2499197114016.
The previous prime is 2499197114003. The next prime is 2499197114083. The reversal of 2499197114017 is 7104117919942.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2003368483216 + 495828630801 = 1415404^2 + 704151^2 .
It is a cyclic number.
It is not a de Polignac number, because 2499197114017 - 227 = 2499062896289 is a prime.
It is not a weakly prime, because it can be changed into another prime (2499197114717) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1249598557008 + 1249598557009.
It is an arithmetic number, because the mean of its divisors is an integer number (1249598557009).
Almost surely, 22499197114017 is an apocalyptic number.
It is an amenable number.
2499197114017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2499197114017 is an equidigital number, since it uses as much as digits as its factorization.
2499197114017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1143072, while the sum is 55.
The spelling of 2499197114017 in words is "two trillion, four hundred ninety-nine billion, one hundred ninety-seven million, one hundred fourteen thousand, seventeen".
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