Base | Representation |
---|---|
bin | 1001010100000011… |
… | …1011110000011011 |
3 | 20110020021200210111 |
4 | 2111000323300123 |
5 | 20110003044242 |
6 | 1052024425151 |
7 | 115645034233 |
oct | 22500736033 |
9 | 6406250714 |
10 | 2500049947 |
11 | 107323858a |
12 | 5993181b7 |
13 | 30ac490c5 |
14 | 19a064cc3 |
15 | e973a817 |
hex | 9503bc1b |
2500049947 has 2 divisors, whose sum is σ = 2500049948. Its totient is φ = 2500049946.
The previous prime is 2500049911. The next prime is 2500050019. The reversal of 2500049947 is 7499400052.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2500049947 - 223 = 2491661339 is a prime.
It is not a weakly prime, because it can be changed into another prime (2500049047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250024973 + 1250024974.
It is an arithmetic number, because the mean of its divisors is an integer number (1250024974).
Almost surely, 22500049947 is an apocalyptic number.
2500049947 is a deficient number, since it is larger than the sum of its proper divisors (1).
2500049947 is an equidigital number, since it uses as much as digits as its factorization.
2500049947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90720, while the sum is 40.
The square root of 2500049947 is about 50000.4994675053. The cubic root of 2500049947 is about 1357.2178467050.
Adding to 2500049947 its reverse (7499400052), we get a palindrome (9999449999).
It can be divided in two parts, 25000 and 49947, that added together give a palindrome (74947).
The spelling of 2500049947 in words is "two billion, five hundred million, forty-nine thousand, nine hundred forty-seven".
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