Base | Representation |
---|---|
bin | 111000110110001010001110… |
… | …000111000111101010101011 |
3 | 1012210012221210011000201220022 |
4 | 320312022032013013222223 |
5 | 230232200424203444433 |
6 | 2243422043000151055 |
7 | 103442542044564542 |
oct | 7066121607075253 |
9 | 1183187704021808 |
10 | 250012430531243 |
11 | 72730749251556 |
12 | 2405a10116848b |
13 | a9670c00b7993 |
14 | 45a49480bb159 |
15 | 1dd85e5164698 |
hex | e3628e1c7aab |
250012430531243 has 2 divisors, whose sum is σ = 250012430531244. Its totient is φ = 250012430531242.
The previous prime is 250012430531231. The next prime is 250012430531287. The reversal of 250012430531243 is 342135034210052.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 250012430531243 - 238 = 249737552624299 is a prime.
It is not a weakly prime, because it can be changed into another prime (250012430536243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125006215265621 + 125006215265622.
It is an arithmetic number, because the mean of its divisors is an integer number (125006215265622).
Almost surely, 2250012430531243 is an apocalyptic number.
250012430531243 is a deficient number, since it is larger than the sum of its proper divisors (1).
250012430531243 is an equidigital number, since it uses as much as digits as its factorization.
250012430531243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 250012430531243 its reverse (342135034210052), we get a palindrome (592147464741295).
The spelling of 250012430531243 in words is "two hundred fifty trillion, twelve billion, four hundred thirty million, five hundred thirty-one thousand, two hundred forty-three".
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