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250012441220561 is a prime number
BaseRepresentation
bin111000110110001010001110…
…101111111001010111010001
31012210012221210220010210212222
4320312022032233321113101
5230232200434423024221
62243422044021230425
7103442542234464665
oct7066121657712721
91183187726123788
10250012441220561
11727307542925a8
122405a104862415
13a9670c238b216
1445a49496a08a5
151dd85e60769ab
hexe3628ebf95d1

250012441220561 has 2 divisors, whose sum is σ = 250012441220562. Its totient is φ = 250012441220560.

The previous prime is 250012441220527. The next prime is 250012441220587. The reversal of 250012441220561 is 165022144210052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189643332921025 + 60369108299536 = 13771105^2 + 7769756^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-250012441220561 is a prime.

It is not a weakly prime, because it can be changed into another prime (250012441229561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125006220610280 + 125006220610281.

It is an arithmetic number, because the mean of its divisors is an integer number (125006220610281).

Almost surely, 2250012441220561 is an apocalyptic number.

It is an amenable number.

250012441220561 is a deficient number, since it is larger than the sum of its proper divisors (1).

250012441220561 is an equidigital number, since it uses as much as digits as its factorization.

250012441220561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 35.

The spelling of 250012441220561 in words is "two hundred fifty trillion, twelve billion, four hundred forty-one million, two hundred twenty thousand, five hundred sixty-one".