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250050325253441 is a prime number
BaseRepresentation
bin111000110110101101100000…
…110100000000110101000001
31012210100120121002122002011212
4320312231200310000311001
5230233311031231102231
62243451311131415505
7103445353106450306
oct7066554064006501
91183316532562155
10250050325253441
1172745824897189
1224065517bb4595
13a96a84bc5201b
1445a6700c270ad
151dd95b1de042b
hexe36b60d00d41

250050325253441 has 2 divisors, whose sum is σ = 250050325253442. Its totient is φ = 250050325253440.

The previous prime is 250050325253419. The next prime is 250050325253461. The reversal of 250050325253441 is 144352523050052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 169021450680625 + 81028874572816 = 13000825^2 + 9001604^2 .

It is a cyclic number.

It is not a de Polignac number, because 250050325253441 - 238 = 249775447346497 is a prime.

It is not a weakly prime, because it can be changed into another prime (250050325253461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125025162626720 + 125025162626721.

It is an arithmetic number, because the mean of its divisors is an integer number (125025162626721).

Almost surely, 2250050325253441 is an apocalyptic number.

It is an amenable number.

250050325253441 is a deficient number, since it is larger than the sum of its proper divisors (1).

250050325253441 is an equidigital number, since it uses as much as digits as its factorization.

250050325253441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720000, while the sum is 41.

The spelling of 250050325253441 in words is "two hundred fifty trillion, fifty billion, three hundred twenty-five million, two hundred fifty-three thousand, four hundred forty-one".