250113050441 has 4 divisors (see below), whose sum is σ = 251159548800. Its totient is φ = 249066552084.

The previous prime is 250113050431. The next prime is 250113050449. The reversal of 250113050441 is 144050311052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-250113050441 is a prime.

It is a super-3 number, since 3×250113050441³ (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 250113050441.

It is not an unprimeable number, because it can be changed into a prime (250113050449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523248821 + ... + 523249298.

It is an arithmetic number, because the mean of its divisors is an integer number (62789887200).

Almost surely, 2^250113050441 is an apocalyptic number.

It is an amenable number.

250113050441 is a deficient number, since it is larger than the sum of its proper divisors (1046498359).

250113050441 is a wasteful number, since it uses less digits than its factorization.

250113050441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1046498358.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 250113050441 its reverse (144050311052), we get a palindrome (394163361493).

The spelling of 250113050441 in words is "two hundred fifty billion, one hundred thirteen million, fifty thousand, four hundred forty-one".