Search a number
-
+
250342415131 = 557449447783
BaseRepresentation
bin1110100100100110010…
…0100001101100011011
3212221011210102100101011
43221021210201230123
513100200124241011
6311001122434351
724041501263414
oct3511144415433
9787153370334
10250342415131
1197195848866
12406272029b7
131a7b7cba8b3
14c18c0a680b
1567a2e05621
hex3a49921b1b

250342415131 has 4 divisors (see below), whose sum is σ = 250791863472. Its totient is φ = 249892966792.

The previous prime is 250342415129. The next prime is 250342415171. The reversal of 250342415131 is 131514243052.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 250342415131 - 21 = 250342415129 is a prime.

It is a super-2 number, since 2×2503424151312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 250342415093 and 250342415102.

It is not an unprimeable number, because it can be changed into a prime (250342415171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224723335 + ... + 224724448.

It is an arithmetic number, because the mean of its divisors is an integer number (62697965868).

Almost surely, 2250342415131 is an apocalyptic number.

250342415131 is a deficient number, since it is larger than the sum of its proper divisors (449448341).

250342415131 is an equidigital number, since it uses as much as digits as its factorization.

250342415131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 449448340.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 250342415131 its reverse (131514243052), we get a palindrome (381856658183).

The spelling of 250342415131 in words is "two hundred fifty billion, three hundred forty-two million, four hundred fifteen thousand, one hundred thirty-one".

Divisors: 1 557 449447783 250342415131