Base | Representation |
---|---|
bin | 1011011000100111100100… |
… | …11011010010010010100001 |
3 | 10021122100001201100220001221 |
4 | 11230103302123102102201 |
5 | 11240133424434441121 |
6 | 125124552154455041 |
7 | 5162505011215144 |
oct | 554236233222241 |
9 | 107570051326057 |
10 | 25035136640161 |
11 | 7a82383a7238a |
12 | 2983b88734481 |
13 | 10c7a599a092b |
14 | 6279c831c05b |
15 | 2d634c128b41 |
hex | 16c4f26d24a1 |
25035136640161 has 2 divisors, whose sum is σ = 25035136640162. Its totient is φ = 25035136640160.
The previous prime is 25035136640131. The next prime is 25035136640167. The reversal of 25035136640161 is 16104663153052.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15449270469136 + 9585866171025 = 3930556^2 + 3096105^2 .
It is a cyclic number.
It is not a de Polignac number, because 25035136640161 - 213 = 25035136631969 is a prime.
It is not a weakly prime, because it can be changed into another prime (25035136640167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12517568320080 + 12517568320081.
It is an arithmetic number, because the mean of its divisors is an integer number (12517568320081).
Almost surely, 225035136640161 is an apocalyptic number.
It is an amenable number.
25035136640161 is a deficient number, since it is larger than the sum of its proper divisors (1).
25035136640161 is an equidigital number, since it uses as much as digits as its factorization.
25035136640161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 43.
The spelling of 25035136640161 in words is "twenty-five trillion, thirty-five billion, one hundred thirty-six million, six hundred forty thousand, one hundred sixty-one".
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