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2505040131 = 31126900937
BaseRepresentation
bin1001010101001111…
…1110000100000011
320110120200020001010
42111103332010003
520112242241011
61052323412003
7116035326666
oct22523760403
96416606033
102505040131
111076036800
1259ab24003
1330bca5589
1419a9a36dd
15e9dc41a6
hex954fe103

2505040131 has 12 divisors (see below), whose sum is σ = 3671299016. Its totient is φ = 1518205920.

The previous prime is 2505040129. The next prime is 2505040133. The reversal of 2505040131 is 1310405052.

It is an interprime number because it is at equal distance from previous prime (2505040129) and next prime (2505040133).

It is not a de Polignac number, because 2505040131 - 21 = 2505040129 is a prime.

It is a super-2 number, since 2×25050401312 = 12550452115840994322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2505040098 and 2505040107.

It is not an unprimeable number, because it can be changed into a prime (2505040133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3450106 + ... + 3450831.

Almost surely, 22505040131 is an apocalyptic number.

2505040131 is a deficient number, since it is larger than the sum of its proper divisors (1166258885).

2505040131 is a wasteful number, since it uses less digits than its factorization.

2505040131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6900962 (or 6900951 counting only the distinct ones).

The product of its (nonzero) digits is 600, while the sum is 21.

The square root of 2505040131 is about 50050.3759326541. The cubic root of 2505040131 is about 1358.1202640825.

Adding to 2505040131 its reverse (1310405052), we get a palindrome (3815445183).

The spelling of 2505040131 in words is "two billion, five hundred five million, forty thousand, one hundred thirty-one".

Divisors: 1 3 11 33 121 363 6900937 20702811 75910307 227730921 835013377 2505040131