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250666520102113 is a prime number
BaseRepresentation
bin111000111111101011011000…
…111000110100010011100001
31012212112111002202221200121011
4320333223120320310103201
5230323410013121231423
62245042335401500521
7103541026021316503
oct7077533070642341
91185474082850534
10250666520102113
117296308a80a235
1224144a264a1741
13a9b399cb3810b
1445c8477c7dd73
151dea6288e1b0d
hexe3fad8e344e1

250666520102113 has 2 divisors, whose sum is σ = 250666520102114. Its totient is φ = 250666520102112.

The previous prime is 250666520102093. The next prime is 250666520102137. The reversal of 250666520102113 is 311201025666052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 249523346430864 + 1143173671249 = 15796308^2 + 1069193^2 .

It is a cyclic number.

It is not a de Polignac number, because 250666520102113 - 213 = 250666520093921 is a prime.

It is a super-3 number, since 3×2506665201021133 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (250666520108113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125333260051056 + 125333260051057.

It is an arithmetic number, because the mean of its divisors is an integer number (125333260051057).

Almost surely, 2250666520102113 is an apocalyptic number.

It is an amenable number.

250666520102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

250666520102113 is an equidigital number, since it uses as much as digits as its factorization.

250666520102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 40.

Adding to 250666520102113 its reverse (311201025666052), we get a palindrome (561867545768165).

The spelling of 250666520102113 in words is "two hundred fifty trillion, six hundred sixty-six billion, five hundred twenty million, one hundred two thousand, one hundred thirteen".