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25080113 is a prime number
BaseRepresentation
bin101111110101…
…1000100110001
31202012012110002
41133223010301
522410030423
62253315345
7423114602
oct137530461
952165402
1025080113
1113180073
128495b55
135271806
14348bda9
152306228
hex17eb131

25080113 has 2 divisors, whose sum is σ = 25080114. Its totient is φ = 25080112.

The previous prime is 25080109. The next prime is 25080131. The reversal of 25080113 is 31108052.

Together with next prime (25080131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25080064 + 49 = 5008^2 + 7^2 .

It is a cyclic number.

It is not a de Polignac number, because 25080113 - 22 = 25080109 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (25080103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12540056 + 12540057.

It is an arithmetic number, because the mean of its divisors is an integer number (12540057).

Almost surely, 225080113 is an apocalyptic number.

It is an amenable number.

25080113 is a deficient number, since it is larger than the sum of its proper divisors (1).

25080113 is an equidigital number, since it uses as much as digits as its factorization.

25080113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 25080113 is about 5008.0048921701. The cubic root of 25080113 is about 292.7137765626.

Adding to 25080113 its reverse (31108052), we get a palindrome (56188165).

The spelling of 25080113 in words is "twenty-five million, eighty thousand, one hundred thirteen".