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251020121432953 is a prime number
BaseRepresentation
bin111001000100110100101101…
…001010110110001101111001
31012220210021210212020110010211
4321010310231022312031321
5230400203202041323303
62245513015105311121
7103605414421121545
oct7104645512661571
91186707725213124
10251020121432953
1172a8a043516764
12241a146a9354a1
13aa0b132861522
1445db61db2aa25
151e04921bbb66d
hexe44d2d2b6379

251020121432953 has 2 divisors, whose sum is σ = 251020121432954. Its totient is φ = 251020121432952.

The previous prime is 251020121432797. The next prime is 251020121432981. The reversal of 251020121432953 is 359234121020152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207051724261264 + 43968397171689 = 14389292^2 + 6630867^2 .

It is a cyclic number.

It is not a de Polignac number, because 251020121432953 - 229 = 251019584562041 is a prime.

It is a super-2 number, since 2×2510201214329532 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (251020121435953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125510060716476 + 125510060716477.

It is an arithmetic number, because the mean of its divisors is an integer number (125510060716477).

Almost surely, 2251020121432953 is an apocalyptic number.

It is an amenable number.

251020121432953 is a deficient number, since it is larger than the sum of its proper divisors (1).

251020121432953 is an equidigital number, since it uses as much as digits as its factorization.

251020121432953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 251020121432953 in words is "two hundred fifty-one trillion, twenty billion, one hundred twenty-one million, four hundred thirty-two thousand, nine hundred fifty-three".