Base | Representation |
---|---|
bin | 1011011010111000111000… |
… | …11001000100111001001001 |
3 | 10021220210102121111001101210 |
4 | 11231130130121010321021 |
5 | 11242423212412143101 |
6 | 125224453310203333 |
7 | 5201236161630315 |
oct | 555343431047111 |
9 | 107823377431353 |
10 | 25113150115401 |
11 | 80024775a5a67 |
12 | 299711b1b3549 |
13 | 11022103989ba |
14 | 62b6a9308b45 |
15 | 2d83b5ee77d6 |
hex | 16d71c644e49 |
25113150115401 has 16 divisors (see below), whose sum is σ = 33671639900160. Its totient is φ = 16648382299920.
The previous prime is 25113150115399. The next prime is 25113150115421. The reversal of 25113150115401 is 10451105131152.
It is not a de Polignac number, because 25113150115401 - 21 = 25113150115399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (25113150115421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61089936 + ... + 61499646.
It is an arithmetic number, because the mean of its divisors is an integer number (2104477493760).
Almost surely, 225113150115401 is an apocalyptic number.
It is an amenable number.
25113150115401 is a deficient number, since it is larger than the sum of its proper divisors (8558489784759).
25113150115401 is a wasteful number, since it uses less digits than its factorization.
25113150115401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 524036.
The product of its (nonzero) digits is 3000, while the sum is 30.
Adding to 25113150115401 its reverse (10451105131152), we get a palindrome (35564255246553).
The spelling of 25113150115401 in words is "twenty-five trillion, one hundred thirteen billion, one hundred fifty million, one hundred fifteen thousand, four hundred one".
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