Base | Representation |
---|---|
bin | 111001000110011100011101… |
… | …000011011100010011100011 |
3 | 1012221011221100102200110110221 |
4 | 321012130131003130103203 |
5 | 230404014323133043201 |
6 | 2250040121103503511 |
7 | 103616440116064642 |
oct | 7106343503342343 |
9 | 1187157312613427 |
10 | 251131520206051 |
11 | 730223091977a1 |
12 | 241bab79bb7b97 |
13 | aa187a6a9a604 |
14 | 4602b8a9c3359 |
15 | 1e077919b54a1 |
hex | e4671d0dc4e3 |
251131520206051 has 2 divisors, whose sum is σ = 251131520206052. Its totient is φ = 251131520206050.
The previous prime is 251131520205997. The next prime is 251131520206087. The reversal of 251131520206051 is 150602025131152.
251131520206051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 251131520206051 - 215 = 251131520173283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 251131520205998 and 251131520206016.
It is not a weakly prime, because it can be changed into another prime (251131520200051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125565760103025 + 125565760103026.
It is an arithmetic number, because the mean of its divisors is an integer number (125565760103026).
Almost surely, 2251131520206051 is an apocalyptic number.
251131520206051 is a deficient number, since it is larger than the sum of its proper divisors (1).
251131520206051 is an equidigital number, since it uses as much as digits as its factorization.
251131520206051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 34.
The spelling of 251131520206051 in words is "two hundred fifty-one trillion, one hundred thirty-one billion, five hundred twenty million, two hundred six thousand, fifty-one".
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