Search a number
-
+
25117512131 is a prime number
BaseRepresentation
bin10111011001000111…
…101101000111000011
32101211111000211011002
4113121013231013003
5402420040342011
615312215242215
71546302221225
oct273107550703
971744024132
1025117512131
11a71a1a9698
124a4b97936b
1324a399bc1a
141303c16415
159c0185c3b
hex5d91ed1c3

25117512131 has 2 divisors, whose sum is σ = 25117512132. Its totient is φ = 25117512130.

The previous prime is 25117512113. The next prime is 25117512169. The reversal of 25117512131 is 13121571152.

Together with previous prime (25117512113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25117512131 - 226 = 25050403267 is a prime.

It is a super-2 number, since 2×251175121312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25117512094 and 25117512103.

It is not a weakly prime, because it can be changed into another prime (25117511131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12558756065 + 12558756066.

It is an arithmetic number, because the mean of its divisors is an integer number (12558756066).

Almost surely, 225117512131 is an apocalyptic number.

25117512131 is a deficient number, since it is larger than the sum of its proper divisors (1).

25117512131 is an equidigital number, since it uses as much as digits as its factorization.

25117512131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2100, while the sum is 29.

The spelling of 25117512131 in words is "twenty-five billion, one hundred seventeen million, five hundred twelve thousand, one hundred thirty-one".