Base | Representation |
---|---|
bin | 111001001001000110101100… |
… | …100000010101111011000001 |
3 | 1012221211102011202101002021211 |
4 | 321021012230200111323001 |
5 | 230420013204240103101 |
6 | 2250300111442250121 |
7 | 103635601006633015 |
oct | 7111065440257301 |
9 | 1187742152332254 |
10 | 251314315550401 |
11 | 73092891417514 |
12 | 2422a493956941 |
13 | aa2cab889bc6c |
14 | 460b96bb50545 |
15 | 1e0c3de7d8c51 |
hex | e491ac815ec1 |
251314315550401 has 8 divisors (see below), whose sum is σ = 251487708308480. Its totient is φ = 251140928090832.
The previous prime is 251314315550371. The next prime is 251314315550449. The reversal of 251314315550401 is 104055513413152.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 251314315550401 - 221 = 251314313453249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (251314315557401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 96036736 + ... + 98618878.
It is an arithmetic number, because the mean of its divisors is an integer number (31435963538560).
Almost surely, 2251314315550401 is an apocalyptic number.
It is an amenable number.
251314315550401 is a deficient number, since it is larger than the sum of its proper divisors (173392758079).
251314315550401 is a wasteful number, since it uses less digits than its factorization.
251314315550401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2649255.
The product of its (nonzero) digits is 180000, while the sum is 40.
Adding to 251314315550401 its reverse (104055513413152), we get a palindrome (355369828963553).
The spelling of 251314315550401 in words is "two hundred fifty-one trillion, three hundred fourteen billion, three hundred fifteen million, five hundred fifty thousand, four hundred one".
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