2513312655041 has 4 divisors (see below), whose sum is σ = 2515731628800. Its totient is φ = 2510893681284.

The previous prime is 2513312654981. The next prime is 2513312655107. The reversal of 2513312655041 is 1405562133152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2513312655041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2513312654986 and 2513312655004.

It is not an unprimeable number, because it can be changed into a prime (2513312655541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1209485321 + ... + 1209487398.

It is an arithmetic number, because the mean of its divisors is an integer number (628932907200).

Almost surely, 2^{2513312655041} is an apocalyptic number.

It is an amenable number.

2513312655041 is a deficient number, since it is larger than the sum of its proper divisors (2418973759).

2513312655041 is a wasteful number, since it uses less digits than its factorization.

2513312655041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2418973758.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 2513312655041 its reverse (1405562133152), we get a palindrome (3918874788193).

The spelling of 2513312655041 in words is "two trillion, five hundred thirteen billion, three hundred twelve million, six hundred fifty-five thousand, forty-one".