Base | Representation |
---|---|
bin | 1110101000010010010… |
… | …1001101110001110001 |
3 | 220000201210100101212122 |
4 | 3222010211031301301 |
5 | 13104212101421231 |
6 | 311243250404025 |
7 | 24105152405561 |
oct | 3520445156161 |
9 | 800653311778 |
10 | 251332451441 |
11 | 97653686795 |
12 | 40862890615 |
13 | 1a9151498b6 |
14 | c24377cda1 |
15 | 680ecb977b |
hex | 3a8494dc71 |
251332451441 has 2 divisors, whose sum is σ = 251332451442. Its totient is φ = 251332451440.
The previous prime is 251332451197. The next prime is 251332451477. The reversal of 251332451441 is 144154233152.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 155390486416 + 95941965025 = 394196^2 + 309745^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-251332451441 is a prime.
It is a super-2 number, since 2×2513324514412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (251332451141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125666225720 + 125666225721.
It is an arithmetic number, because the mean of its divisors is an integer number (125666225721).
Almost surely, 2251332451441 is an apocalyptic number.
It is an amenable number.
251332451441 is a deficient number, since it is larger than the sum of its proper divisors (1).
251332451441 is an equidigital number, since it uses as much as digits as its factorization.
251332451441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 57600, while the sum is 35.
Adding to 251332451441 its reverse (144154233152), we get a palindrome (395486684593).
The spelling of 251332451441 in words is "two hundred fifty-one billion, three hundred thirty-two million, four hundred fifty-one thousand, four hundred forty-one".
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