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2513785116675 = 352721925033767
BaseRepresentation
bin100100100101001001010…
…001001101100000000011
322220022112000012001021110
4210211021101031200003
5312141212442213200
65202452243054403
7346420636640100
oct44451121154003
98808460161243
102513785116675
1188a0aa189498
12347231671403
13153083625501
148994c811aa7
15455c8e49b50
hex2494944d803

2513785116675 has 216 divisors, whose sum is σ = 5114026181376. Its totient is φ = 1086224065920.

The previous prime is 2513785116671. The next prime is 2513785116701. The reversal of 2513785116675 is 5766115873152.

It is not a de Polignac number, because 2513785116675 - 22 = 2513785116671 is a prime.

It is a super-2 number, since 2×25137851166752 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (57).

It is not an unprimeable number, because it can be changed into a prime (2513785116671) by changing a digit.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 667315642 + ... + 667319408.

It is an arithmetic number, because the mean of its divisors is an integer number (23676047136).

Almost surely, 22513785116675 is an apocalyptic number.

2513785116675 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

2513785116675 is an abundant number, since it is smaller than the sum of its proper divisors (2600241064701).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2513785116675 is a wasteful number, since it uses less digits than its factorization.

2513785116675 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4335 (or 4304 counting only the distinct ones).

The product of its digits is 10584000, while the sum is 57.

The spelling of 2513785116675 in words is "two trillion, five hundred thirteen billion, seven hundred eighty-five million, one hundred sixteen thousand, six hundred seventy-five".