Base | Representation |
---|---|
bin | 111001001010100100110000… |
… | …111011000101001101010001 |
3 | 1012222012001220000200212222202 |
4 | 321022210300323011031101 |
5 | 230423142034234301040 |
6 | 2250414334300212545 |
7 | 103646105016325040 |
oct | 7112446073051521 |
9 | 1188161800625882 |
10 | 251415321400145 |
11 | 731217036013a1 |
12 | 24245b8253a155 |
13 | aa394948b6366 |
14 | 46127d0602557 |
15 | 1e0ed51ead015 |
hex | e4a930ec5351 |
251415321400145 has 16 divisors (see below), whose sum is σ = 344802935911680. Its totient is φ = 172396687107264.
The previous prime is 251415321400129. The next prime is 251415321400147. The reversal of 251415321400145 is 541004123514152.
It is a cyclic number.
It is not a de Polignac number, because 251415321400145 - 24 = 251415321400129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 251415321400099 and 251415321400108.
It is not an unprimeable number, because it can be changed into a prime (251415321400147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47238365 + ... + 52290474.
It is an arithmetic number, because the mean of its divisors is an integer number (21550183494480).
Almost surely, 2251415321400145 is an apocalyptic number.
It is an amenable number.
251415321400145 is a deficient number, since it is larger than the sum of its proper divisors (93387614511535).
251415321400145 is an equidigital number, since it uses as much as digits as its factorization.
251415321400145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99601024.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 251415321400145 its reverse (541004123514152), we get a palindrome (792419444914297).
The spelling of 251415321400145 in words is "two hundred fifty-one trillion, four hundred fifteen billion, three hundred twenty-one million, four hundred thousand, one hundred forty-five".
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