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25143403139 is a prime number
BaseRepresentation
bin10111011010101010…
…011110001010000011
32101220021202012221022
4113122222132022003
5402443202400024
615314542220055
71550035254221
oct273252361203
971807665838
1025143403139
11a732882a18
124a5858462b
1324a916584a
141307435b11
159c259c35e
hex5daa9e283

25143403139 has 2 divisors, whose sum is σ = 25143403140. Its totient is φ = 25143403138.

The previous prime is 25143403123. The next prime is 25143403147. The reversal of 25143403139 is 93130434152.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25143403139 - 24 = 25143403123 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25143403099 and 25143403108.

It is not a weakly prime, because it can be changed into another prime (25143402139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12571701569 + 12571701570.

It is an arithmetic number, because the mean of its divisors is an integer number (12571701570).

Almost surely, 225143403139 is an apocalyptic number.

25143403139 is a deficient number, since it is larger than the sum of its proper divisors (1).

25143403139 is an equidigital number, since it uses as much as digits as its factorization.

25143403139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

The spelling of 25143403139 in words is "twenty-five billion, one hundred forty-three million, four hundred three thousand, one hundred thirty-nine".