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2514512113 is a prime number
BaseRepresentation
bin1001010111100000…
…0110100011110001
320111020111110011021
42111320012203301
520122203341423
61053302415441
7116212000051
oct22570064361
96436443137
102514512113
111080416193
125a2131581
13310c409b9
1419bd4b561
15eab4595d
hex95e068f1

2514512113 has 2 divisors, whose sum is σ = 2514512114. Its totient is φ = 2514512112.

The previous prime is 2514512101. The next prime is 2514512131. The reversal of 2514512113 is 3112154152.

Together with next prime (2514512131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2213420209 + 301091904 = 47047^2 + 17352^2 .

It is a cyclic number.

It is not a de Polignac number, because 2514512113 - 25 = 2514512081 is a prime.

It is not a weakly prime, because it can be changed into another prime (2514512183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1257256056 + 1257256057.

It is an arithmetic number, because the mean of its divisors is an integer number (1257256057).

Almost surely, 22514512113 is an apocalyptic number.

It is an amenable number.

2514512113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2514512113 is an equidigital number, since it uses as much as digits as its factorization.

2514512113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1200, while the sum is 25.

The square root of 2514512113 is about 50144.9111376219. The cubic root of 2514512113 is about 1359.8298722094.

Adding to 2514512113 its reverse (3112154152), we get a palindrome (5626666265).

The spelling of 2514512113 in words is "two billion, five hundred fourteen million, five hundred twelve thousand, one hundred thirteen".