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2520044393 = 7135493583
BaseRepresentation
bin1001011000110100…
…1101001101101001
320111121220112000112
42112031031031221
520130112410033
61054021144105
7116310011126
oct22615151551
96447815015
102520044393
111083554719
125a3b5b035
13312129b39
1419c98b74d
15eb389c48
hex9634d369

2520044393 has 4 divisors (see below), whose sum is σ = 2555538048. Its totient is φ = 2484550740.

The previous prime is 2520044333. The next prime is 2520044479. The reversal of 2520044393 is 3934400252.

2520044393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2520044393 - 212 = 2520040297 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2520044333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17746721 + ... + 17746862.

It is an arithmetic number, because the mean of its divisors is an integer number (638884512).

Almost surely, 22520044393 is an apocalyptic number.

It is an amenable number.

2520044393 is a deficient number, since it is larger than the sum of its proper divisors (35493655).

2520044393 is an equidigital number, since it uses as much as digits as its factorization.

2520044393 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35493654.

The product of its (nonzero) digits is 25920, while the sum is 32.

The square root of 2520044393 is about 50200.0437549610. The cubic root of 2520044393 is about 1360.8264139919.

The spelling of 2520044393 in words is "two billion, five hundred twenty million, forty-four thousand, three hundred ninety-three".

Divisors: 1 71 35493583 2520044393