Base | Representation |
---|---|
bin | 1011011101011101000010… |
… | …11101000101010111111001 |
3 | 10022020012220122221122112101 |
4 | 11232232201131011113321 |
5 | 11300344211130202333 |
6 | 125333150431543401 |
7 | 5210506154400136 |
oct | 556564135052771 |
9 | 108205818848471 |
10 | 25201281881593 |
11 | 8036892698374 |
12 | 29b021638ab61 |
13 | 110a61712a28c |
14 | 631a6a04b58d |
15 | 2da82333d67d |
hex | 16eba17455f9 |
25201281881593 has 2 divisors, whose sum is σ = 25201281881594. Its totient is φ = 25201281881592.
The previous prime is 25201281881569. The next prime is 25201281881641. The reversal of 25201281881593 is 39518818210252.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20448149373369 + 4753132508224 = 4521963^2 + 2180168^2 .
It is a cyclic number.
It is not a de Polignac number, because 25201281881593 - 213 = 25201281873401 is a prime.
It is not a weakly prime, because it can be changed into another prime (25201281881563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12600640940796 + 12600640940797.
It is an arithmetic number, because the mean of its divisors is an integer number (12600640940797).
Almost surely, 225201281881593 is an apocalyptic number.
It is an amenable number.
25201281881593 is a deficient number, since it is larger than the sum of its proper divisors (1).
25201281881593 is an equidigital number, since it uses as much as digits as its factorization.
25201281881593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2764800, while the sum is 55.
The spelling of 25201281881593 in words is "twenty-five trillion, two hundred one billion, two hundred eighty-one million, eight hundred eighty-one thousand, five hundred ninety-three".
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