2520130035 has 16 divisors (see below), whose sum is σ = 4040499456. Its totient is φ = 1341305568.

The previous prime is 2520129973. The next prime is 2520130043. The reversal of 2520130035 is 5300310252.

2520130035 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 2520130035 - 2⁹ = 2520129523 is a prime.

It is a super-3 number, since 3×2520130035³ (a number of 29 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2520129993 and 2520130020.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165189 + ... + 179798.

It is an arithmetic number, because the mean of its divisors is an integer number (252531216).

Almost surely, 2^2520130035 is an apocalyptic number.

2520130035 is a deficient number, since it is larger than the sum of its proper divisors (1520369421).

2520130035 is a wasteful number, since it uses less digits than its factorization.

2520130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 345482.

The product of its (nonzero) digits is 900, while the sum is 21.

The square root of 2520130035 is about 50200.8967549386. The cubic root of 2520130035 is about 1360.8418294050.

Adding to 2520130035 its reverse (5300310252), we get a palindrome (7820440287).

The spelling of 2520130035 in words is "two billion, five hundred twenty million, one hundred thirty thousand, thirty-five".