Base | Representation |
---|---|
bin | 1001011000110110… |
… | …0110100001100011 |
3 | 20111122002210020022 |
4 | 2112031212201203 |
5 | 20130124214232 |
6 | 1054023304055 |
7 | 116310622313 |
oct | 22615464143 |
9 | 6448083208 |
10 | 2520148067 |
11 | 10836155a8 |
12 | 5a3bab02b |
13 | 312165098 |
14 | 19c9b7443 |
15 | eb3aa812 |
hex | 96366863 |
2520148067 has 2 divisors, whose sum is σ = 2520148068. Its totient is φ = 2520148066.
The previous prime is 2520148027. The next prime is 2520148073. The reversal of 2520148067 is 7608410252.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2520148067 - 210 = 2520147043 is a prime.
It is a super-3 number, since 3×25201480673 (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2520148027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1260074033 + 1260074034.
It is an arithmetic number, because the mean of its divisors is an integer number (1260074034).
Almost surely, 22520148067 is an apocalyptic number.
2520148067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2520148067 is an equidigital number, since it uses as much as digits as its factorization.
2520148067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 35.
The square root of 2520148067 is about 50201.0763530026. The cubic root of 2520148067 is about 1360.8450750895.
The spelling of 2520148067 in words is "two billion, five hundred twenty million, one hundred forty-eight thousand, sixty-seven".
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