Base | Representation |
---|---|
bin | 111001010011011000011001… |
… | …001111101101011011001111 |
3 | 1020001022220222222100221122202 |
4 | 321103120121033231123033 |
5 | 231013101003210341221 |
6 | 2252000343121432115 |
7 | 104040611201216123 |
oct | 7123303117553317 |
9 | 1201286888327582 |
10 | 252020514543311 |
11 | 73335333331248 |
12 | 2432332049b63b |
13 | aa815813c8737 |
14 | 4633c02463583 |
15 | 1e20972bd4d0b |
hex | e536193ed6cf |
252020514543311 has 16 divisors (see below), whose sum is σ = 265772229645600. Its totient is φ = 238611141245568.
The previous prime is 252020514543293. The next prime is 252020514543383. The reversal of 252020514543311 is 113345415020252.
It is a cyclic number.
It is not a de Polignac number, because 252020514543311 - 222 = 252020510349007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (252020514443311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41042876 + ... + 46782033.
It is an arithmetic number, because the mean of its divisors is an integer number (16610764352850).
Almost surely, 2252020514543311 is an apocalyptic number.
252020514543311 is a deficient number, since it is larger than the sum of its proper divisors (13751715102289).
252020514543311 is a wasteful number, since it uses less digits than its factorization.
252020514543311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87826858.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 252020514543311 its reverse (113345415020252), we get a palindrome (365365929563563).
The spelling of 252020514543311 in words is "two hundred fifty-two trillion, twenty billion, five hundred fourteen million, five hundred forty-three thousand, three hundred eleven".
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