Base | Representation |
---|---|
bin | 111001010011011000011011… |
… | …100010111111001101010001 |
3 | 1020001022221002200000102212202 |
4 | 321103120123202333031101 |
5 | 231013101043101320223 |
6 | 2252000351021132545 |
7 | 104040612150325652 |
oct | 7123303342771521 |
9 | 1201287080012782 |
10 | 252020553151313 |
11 | 73335353100a91 |
12 | 243233313ba155 |
13 | aa815893c57cb |
14 | 4633c07633529 |
15 | 1e209762ae428 |
hex | e5361b8bf351 |
252020553151313 has 2 divisors, whose sum is σ = 252020553151314. Its totient is φ = 252020553151312.
The previous prime is 252020553151309. The next prime is 252020553151333. The reversal of 252020553151313 is 313151355020252.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 234741375697984 + 17279177453329 = 15321272^2 + 4156823^2 .
It is a cyclic number.
It is not a de Polignac number, because 252020553151313 - 22 = 252020553151309 is a prime.
It is not a weakly prime, because it can be changed into another prime (252020553151333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126010276575656 + 126010276575657.
It is an arithmetic number, because the mean of its divisors is an integer number (126010276575657).
Almost surely, 2252020553151313 is an apocalyptic number.
It is an amenable number.
252020553151313 is a deficient number, since it is larger than the sum of its proper divisors (1).
252020553151313 is an equidigital number, since it uses as much as digits as its factorization.
252020553151313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 252020553151313 in words is "two hundred fifty-two trillion, twenty billion, five hundred fifty-three million, one hundred fifty-one thousand, three hundred thirteen".
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