Base | Representation |
---|---|
bin | 1011011101101101010010… |
… | …11110111011000110010001 |
3 | 10022021001102200220000010020 |
4 | 11232312221132323012101 |
5 | 11301020043132003423 |
6 | 125341152255054053 |
7 | 5211235314512316 |
oct | 556665136730621 |
9 | 108231380800106 |
10 | 25210006516113 |
11 | 803a55a500421 |
12 | 29b1a50211329 |
13 | 110b3a7826503 |
14 | 632256a62d0d |
15 | 2dab842754e3 |
hex | 16eda97bb191 |
25210006516113 has 32 divisors (see below), whose sum is σ = 35209404088320. Its totient is φ = 16014266326080.
The previous prime is 25210006516103. The next prime is 25210006516127. The reversal of 25210006516113 is 31161560001252.
It is not a de Polignac number, because 25210006516113 - 218 = 25210006253969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (25210006516103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 131526495 + ... + 131718027.
It is an arithmetic number, because the mean of its divisors is an integer number (1100293877760).
Almost surely, 225210006516113 is an apocalyptic number.
25210006516113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
25210006516113 is a deficient number, since it is larger than the sum of its proper divisors (9999397572207).
25210006516113 is a wasteful number, since it uses less digits than its factorization.
25210006516113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198869.
The product of its (nonzero) digits is 10800, while the sum is 33.
Adding to 25210006516113 its reverse (31161560001252), we get a palindrome (56371566517365).
The spelling of 25210006516113 in words is "twenty-five trillion, two hundred ten billion, six million, five hundred sixteen thousand, one hundred thirteen".
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