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25211250811441 = 198712688098043
BaseRepresentation
bin1011011101101111100111…
…01001100010001000110001
310022021011122102020202102101
411232313303221202020301
511301030120201431231
6125341515544420401
75211311204035432
oct556676351421061
9108234572222371
1025211250811441
118040038910972
1229b2138a77701
13110b545559636
14632334003489
152dac08610661
hex16edf3a62231

25211250811441 has 4 divisors (see below), whose sum is σ = 25223938911472. Its totient is φ = 25198562711412.

The previous prime is 25211250811429. The next prime is 25211250811447. The reversal of 25211250811441 is 14411805211252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25211250811441 - 227 = 25211116593713 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25211250811441.

It is not an unprimeable number, because it can be changed into a prime (25211250811447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6344047035 + ... + 6344051008.

It is an arithmetic number, because the mean of its divisors is an integer number (6305984727868).

Almost surely, 225211250811441 is an apocalyptic number.

It is an amenable number.

25211250811441 is a deficient number, since it is larger than the sum of its proper divisors (12688100031).

25211250811441 is a wasteful number, since it uses less digits than its factorization.

25211250811441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12688100030.

The product of its (nonzero) digits is 25600, while the sum is 37.

The spelling of 25211250811441 in words is "twenty-five trillion, two hundred eleven billion, two hundred fifty million, eight hundred eleven thousand, four hundred forty-one".

Divisors: 1 1987 12688098043 25211250811441