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25211315114 = 212605657557
BaseRepresentation
bin10111011110101101…
…100010001110101010
32102002000112111122122
4113132231202032222
5403113044040424
615325405551242
71551521433266
oct273655421652
972060474578
1025211315114
11a768148217
124a77275522
1324ba252b4b
1413124730a6
159c851445e
hex5deb623aa

25211315114 has 4 divisors (see below), whose sum is σ = 37816972674. Its totient is φ = 12605657556.

The previous prime is 25211315111. The next prime is 25211315117. The reversal of 25211315114 is 41151311252.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (25211315111) and next prime (25211315117).

It can be written as a sum of positive squares in only one way, i.e., 22640318089 + 2570997025 = 150467^2 + 50705^2 .

It is a super-2 number, since 2×252113151142 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (25211315111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6302828777 + ... + 6302828780.

Almost surely, 225211315114 is an apocalyptic number.

25211315114 is a deficient number, since it is larger than the sum of its proper divisors (12605657560).

25211315114 is a wasteful number, since it uses less digits than its factorization.

25211315114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12605657559.

The product of its digits is 1200, while the sum is 26.

Adding to 25211315114 its reverse (41151311252), we get a palindrome (66362626366).

The spelling of 25211315114 in words is "twenty-five billion, two hundred eleven million, three hundred fifteen thousand, one hundred fourteen".

Divisors: 1 2 12605657557 25211315114