Base | Representation |
---|---|
bin | 1110101011001101000… |
… | …0010100101110100011 |
3 | 220002202100210121002120 |
4 | 3222303100110232203 |
5 | 13112313032112120 |
6 | 311453102115323 |
7 | 24133441266003 |
oct | 3526320245643 |
9 | 802670717076 |
10 | 252115504035 |
11 | 97a156a179a |
12 | 40a40b7bb43 |
13 | 1aa0b447925 |
14 | c2b9776003 |
15 | 68588e5140 |
hex | 3ab3414ba3 |
252115504035 has 32 divisors (see below), whose sum is σ = 413264291328. Its totient is φ = 131169089280.
The previous prime is 252115503977. The next prime is 252115504063. The reversal of 252115504035 is 530405511252.
252115504035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 252115504035 - 27 = 252115503907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 252115503987 and 252115504005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12143874 + ... + 12164616.
It is an arithmetic number, because the mean of its divisors is an integer number (12914509104).
Almost surely, 2252115504035 is an apocalyptic number.
252115504035 is a deficient number, since it is larger than the sum of its proper divisors (161148787293).
252115504035 is a wasteful number, since it uses less digits than its factorization.
252115504035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40555.
The product of its (nonzero) digits is 30000, while the sum is 33.
The spelling of 252115504035 in words is "two hundred fifty-two billion, one hundred fifteen million, five hundred four thousand, thirty-five".
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