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2522014133113 = 22711110194419
BaseRepresentation
bin100100101100110011110…
…000011010101101111001
322221002202111112101200001
4210230303300122231321
5312310041104224423
65210333003313001
7350131601265466
oct44546360325571
98832674471601
102522014133113
11892642258322
1234894951b761
13153a95441cc7
148a0cd69266d
154590b5d1cad
hex24b33c1ab79

2522014133113 has 4 divisors (see below), whose sum is σ = 2533124327760. Its totient is φ = 2510903938468.

The previous prime is 2522014133053. The next prime is 2522014133137. The reversal of 2522014133113 is 3113314102252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2522014133113 - 217 = 2522014002041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2522014133173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5555096983 + ... + 5555097436.

It is an arithmetic number, because the mean of its divisors is an integer number (633281081940).

Almost surely, 22522014133113 is an apocalyptic number.

It is an amenable number.

2522014133113 is a deficient number, since it is larger than the sum of its proper divisors (11110194647).

2522014133113 is a wasteful number, since it uses less digits than its factorization.

2522014133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11110194646.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 2522014133113 its reverse (3113314102252), we get a palindrome (5635328235365).

The spelling of 2522014133113 in words is "two trillion, five hundred twenty-two billion, fourteen million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 227 11110194419 2522014133113