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252265675065 = 35499190117729
BaseRepresentation
bin1110101011110000110…
…1001011100100111001
3220010010211101002000120
43222330031023210321
513113120003100230
6311520024523453
724140243600265
oct3527415134471
9803124332016
10252265675065
1197a92440488
1240a83320589
131aa335a6621
14c2d16a70a5
156866baa310
hex3abc34b939

252265675065 has 32 divisors (see below), whose sum is σ = 404669520000. Its totient is φ = 134193868800.

The previous prime is 252265675061. The next prime is 252265675099. The reversal of 252265675065 is 560576562252.

It is not a de Polignac number, because 252265675065 - 22 = 252265675061 is a prime.

It is a super-3 number, since 3×2522656750653 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 252265674999 and 252265675017.

It is not an unprimeable number, because it can be changed into a prime (252265675061) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14220121 + ... + 14237849.

It is an arithmetic number, because the mean of its divisors is an integer number (12645922500).

Almost surely, 2252265675065 is an apocalyptic number.

It is an amenable number.

252265675065 is a deficient number, since it is larger than the sum of its proper divisors (152403844935).

252265675065 is a wasteful number, since it uses less digits than its factorization.

252265675065 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20137.

The product of its (nonzero) digits is 7560000, while the sum is 51.

The spelling of 252265675065 in words is "two hundred fifty-two billion, two hundred sixty-five million, six hundred seventy-five thousand, sixty-five".

Divisors: 1 3 5 15 499 1497 1901 2495 5703 7485 9505 17729 28515 53187 88645 265935 948599 2845797 4742995 8846771 14228985 26540313 33702829 44233855 101108487 132701565 168514145 505542435 16817711671 50453135013 84088558355 252265675065