Base | Representation |
---|---|
bin | 1110101011111100000… |
… | …1110111010011111001 |
3 | 220010021010111110122220 |
4 | 3222333001313103321 |
5 | 13113214114240441 |
6 | 311524440034253 |
7 | 24141360311652 |
oct | 3527701672371 |
9 | 803233443586 |
10 | 252313040121 |
11 | 9800715155a |
12 | 40a97162989 |
13 | 1aa4034b59c |
14 | c2d7ab6529 |
15 | 686ae14466 |
hex | 3abf0774f9 |
252313040121 has 8 divisors (see below), whose sum is σ = 336763855584. Its totient is φ = 168035459040.
The previous prime is 252313040099. The next prime is 252313040123. The reversal of 252313040121 is 121040313252.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 252313040121 - 214 = 252313023737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 252313040091 and 252313040100.
It is not an unprimeable number, because it can be changed into a prime (252313040123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43305196 + ... + 43311021.
It is an arithmetic number, because the mean of its divisors is an integer number (42095481948).
Almost surely, 2252313040121 is an apocalyptic number.
It is an amenable number.
252313040121 is a deficient number, since it is larger than the sum of its proper divisors (84450815463).
252313040121 is an equidigital number, since it uses as much as digits as its factorization.
252313040121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86617191.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 252313040121 its reverse (121040313252), we get a palindrome (373353353373).
The spelling of 252313040121 in words is "two hundred fifty-two billion, three hundred thirteen million, forty thousand, one hundred twenty-one".
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