Search a number
-
+
252313040121 = 397186616217
BaseRepresentation
bin1110101011111100000…
…1110111010011111001
3220010021010111110122220
43222333001313103321
513113214114240441
6311524440034253
724141360311652
oct3527701672371
9803233443586
10252313040121
119800715155a
1240a97162989
131aa4034b59c
14c2d7ab6529
15686ae14466
hex3abf0774f9

252313040121 has 8 divisors (see below), whose sum is σ = 336763855584. Its totient is φ = 168035459040.

The previous prime is 252313040099. The next prime is 252313040123. The reversal of 252313040121 is 121040313252.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 252313040121 - 214 = 252313023737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 252313040091 and 252313040100.

It is not an unprimeable number, because it can be changed into a prime (252313040123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43305196 + ... + 43311021.

It is an arithmetic number, because the mean of its divisors is an integer number (42095481948).

Almost surely, 2252313040121 is an apocalyptic number.

It is an amenable number.

252313040121 is a deficient number, since it is larger than the sum of its proper divisors (84450815463).

252313040121 is an equidigital number, since it uses as much as digits as its factorization.

252313040121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86617191.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 252313040121 its reverse (121040313252), we get a palindrome (373353353373).

The spelling of 252313040121 in words is "two hundred fifty-two billion, three hundred thirteen million, forty thousand, one hundred twenty-one".

Divisors: 1 3 971 2913 86616217 259848651 84104346707 252313040121